Suppose struct_name
is the name of a struct I've defined, and array is a member in the struct defined as char array[o]
what does the following line produce? (*struct_name).array
an address location?
Suppose struct_name
is the name of a struct I've defined, and array is a member in the struct defined as char array[o]
what does the following line produce? (*struct_name).array
an address location?
yes (assuming struct_name is a pointer to your struct, otherwise the dereferencing just doesn't make sense)
btw, why not do struct_name->array ?
If you've defined struct_name
as an instance of your struct like this:
struct your_struct struct_name;
You want struct_name.array
which, yes, produces an address to the array
member. If you've defined struct_name
as an instance of your struct like this:
struct your_struct *struct_name;
struct_name = malloc(sizeof(struct your_struct));
You want struct_name->array
, which also returns the address of array
.
If you've defined struct_name
as the name of the struct itself like this:
typedef struct _struct_name {
char array[5];
} struct_name;
Then you don't know what you want.