I'm trying to display the following code only once while the rest of the code loops threw. How should my code look like and where should I put it. As of right now the bottom code will not display but if I put it in the loop it will display multiple times (not what I want).
//Display only once.
if (!empty($row['category']) && !empty($row['url'])){
echo '<h2>List of Links</h2>';
}
Here is the full code.
// Query member data from the database and ready it for display
$mysqli = new mysqli("localhost", "root", "", "sitename");
$dbc = mysqli_query($mysqli,"SELECT users.*, categories.*, users_categories.* FROM users_categories INNER JOIN users ON users_categories.user_id = users.user_id INNER JOIN categories ON users_categories.category_id = categories.id WHERE users_categories.user_id=3");
if (!$dbc) {
// There was an error...do something about it here...
print mysqli_error($mysqli);
}
//Display only once.
if (!empty($row['category']) && !empty($row['url'])){
echo '<h2>List of Links</h2>';
}
$ctr = 0;
while ($row = mysqli_fetch_assoc($dbc)) {
if (!empty($row['category']) && !empty($row['url'])) {
if ($ctr%3 == 0) {
echo '<div>';
}
$ctr ++;
echo '<p"><a href="' . $row['url'] . '" title="' . $row['category'] . ' Category Link">' . $row['category'] . '</a></p>';
if ($ctr%3 == 0) {
echo '</div>';
}
}
}
if ($ctr%3 != 0) {
echo '</div>';
}