Alternative to eval

Question

In the following statement, how could I make the "log.entries[i]" part a variable?

json.log.entries[i]

eval works but I don’t want to use it.

eval("json" + "var")

I also tried:

json[var]

Thanks

Answer 1

You would have to split it up like this:

json["log"]["entries"][i];

But honestly I think that eval really would be your best option for a situation like this. Why do you need to store this as a string? Perhaps if I knew more about the problem you are trying to solve I could give you a btter solution.

Answer 2

It sounds like the target variable you're trying to refer to is "jsonvariablename", and not a property of an object called "json" which could be referred json.variablename / json[variablename]. This is not a good naming structure for variables and eval is indeed required in this case -- is it possible for you to change the variable format so that the variables are properties of an object called JSON? That would be the best solution.