You can convert the date params to datetime.
SELECT convert(datetime, @StartDate) into datetimevariable
then you can use date functions to add days.
select DATEADD(day,1,datetimevariable) into datetimevariable
As a solution to get a m/d/yyyy format, I C&P this function from some website a couple of weeks ago. Use this code to create the a function and call in this way:
SELECT dbo.fnFormatDate (@DateTimeVariable, 'M/DD/YYYY') into stringVariable
CREATE FUNCTION dbo.CustomFormatDate (@Datetime DATETIME, @FormatMask VARCHAR(32))
RETURNS VARCHAR(32)
AS
BEGIN
DECLARE @StringDate VARCHAR(32)
SET @StringDate = @FormatMask
IF (CHARINDEX (‘YYYY’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘YYYY’,
DATENAME(YY, @Datetime))
IF (CHARINDEX (‘YY’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘YY’,
RIGHT(DATENAME(YY, @Datetime),2))
IF (CHARINDEX (‘Month’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘Month’,
DATENAME(MM, @Datetime))
IF (CHARINDEX (‘MON’,@StringDate COLLATE SQL_Latin1_General_CP1_CS_AS)>0)
SET @StringDate = REPLACE(@StringDate, ‘MON’,
LEFT(UPPER(DATENAME(MM, @Datetime)),3))
IF (CHARINDEX (‘Mon’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘Mon’,
LEFT(DATENAME(MM, @Datetime),3))
IF (CHARINDEX (‘MM’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘MM’,
RIGHT(‘0′+CONVERT(VARCHAR,DATEPART(MM, @Datetime)),2))
IF (CHARINDEX (‘M’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘M’,
CONVERT(VARCHAR,DATEPART(MM, @Datetime)))
IF (CHARINDEX (‘DD’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘DD’,
RIGHT(‘0′+DATENAME(DD, @Datetime),2))
IF (CHARINDEX (‘D’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘D’,
DATENAME(DD, @Datetime))
RETURN @StringDate
END
GO