Hi
I want to create a file with a .aspx extension(or any other extension) completely in memory. Can this be done?
Right now I have a memory stream that has all the stuff I want to write to this file but I don't actually want to create a physical file on the server since then I probably have to enable write permissions for my server. What I want to do is create the file in memory and upload via ftpWebRequest.
Edit.
I must be doing something wrong because I get weird stuff in my file so weird I can't even paste it into my posts.
Basically it is a bunch of squares between everything. Like it almost seems like it fills it in for the spaces. Like If I look closely I will see the tag still but it will have a square between each letter.
Here is a portion of my code. Maybe I am using the wrong encoding?
using (MemoryStream memory = new MemoryStream())
{
UnicodeEncoding uniEncoding = new UnicodeEncoding();
// readByline is the first bunch of data I want for my new file.
memory.Write(uniEncoding.GetBytes(readByLine), 0, readByLine.Length);
// second bunch of data I want for my new file.
memory.Write(uniEncoding.GetBytes(html), 0, html.Length);
// the follow code just figure out the end of the file that I am
// trying to extract some information out of.
string readToEnd = reader.ReadToEnd();
int endIndex = readToEnd.IndexOf(END_FLAG);
endIndex += END_FLAG.Length;
string restOfFile = readToEnd.Substring(endIndex);
// once found I write it the memory stream.
memory.Write(uniEncoding.GetBytes(restOfFile),0,restOfFile.Length);
// now I want to upload my file. I have the same file name already
// existing on the server? Do I have to tell it override it?
FtpWebRequest request2 = (FtpWebRequest)WebRequest.Create(path);
request2.Method = WebRequestMethods.Ftp.UploadFile;
request2.Credentials = new NetworkCredential(ftpUsername, ftpPassword);
// now I am trying your code.
byte[] fileContents = memory.ToArray();
using (Stream writer = request2.GetRequestStream())
{
writer.Write(fileContents, 0, fileContents.Length);
}
FtpWebResponse test = (FtpWebResponse)request2.GetResponse();
return Content("test");
}