I have an application that on a subsequent start detects if there's a process with the same name already running and, if so, activates the running app's window and then exits.
The problem is that the main window could be hidden (only a notification area icon visible), thus leaving me with no window handle.
At startup, previous instance's MainWindowHandle
property is 0, so I can't send ShowWindow
or PostMessage
.
Is there any way I can send a message that can be intercepted by the running app, thus allowing it to display its main window?
The application is written in C#, the code I'm using to achieve this below.
[STAThread]
static void Main()
{
bool createdNew = true;
using (Mutex mutex = new Mutex(true, "MyMutexName", out createdNew))
{
if (createdNew)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new MainForm());
}
else
{
Process current = Process.GetCurrentProcess();
foreach (Process process in Process.GetProcessesByName(current.ProcessName))
{
if (process.Id != current.Id)
{
Interop.WINDOWINFO pwi = new Interop.WINDOWINFO();
IntPtr handle = process.MainWindowHandle;
var isVisible = Interop.GetWindowInfo(handle, ref pwi);
if (!isVisible)
{
MessageBox.Show(Constants.APP_NAME + " is already running, check the notification area (near the clock).",
Constants.APP_NAME, MessageBoxButtons.OK, MessageBoxIcon.Information);//temporary message, until I find the solution
//Interop.ShowWindow(handle, Interop.WindowShowStyle.ShowNormal);
//Interop.PostMessage(handle, Interop.WM_CUSTOM_ACTIVATEAPP, IntPtr.Zero, IntPtr.Zero);
}
else
Interop.SetForegroundWindow(handle);//this works when the window is visible
break;
}
}
}
}
}
}