How to programically select top row of JQGrid?

Question

How does one programically select the top row of a JQGrid. I want to have the top row already selected when it is opened on the page. My grid is sorted by a descriptive column so the first row's id could be any number. I know the method to use I just don't know how to get the rowid for the top (first) row. The method is:

jQuery("#mygrid").setSelection(rowid, true);

I know there must be a simple solution to this but I just can't figure out how to do it.

Answer 1

$("#mygrid").getDataIds()[0];

Answer 2

Or, without using the jqGrid API, you should be able to retrieve the top row by navigating the DOM:

var top_rowid = $('#mygrid tbody:first-child tr:first').attr('id');