Note: No jQuery
How could i do something like this:
var array = new Array();
array[name] = "Tom";
array[age] = 15;
foreach(array as key=>value){
alert(key + " = " + value);
}
Note: No jQuery
How could i do something like this:
var array = new Array();
array[name] = "Tom";
array[age] = 15;
foreach(array as key=>value){
alert(key + " = " + value);
}
First of all, you should call it obj
or person
instead of array
; an array is a sequence of similar elements, not a single object.
You can do it like this:
var person = new Object();
person['name'] = "Tom";
person['age'] = 15;
for (var key in person) {
if(!person.hasOwnProperty(key)) continue; //Skip base props like toString
alert(key + " = " + person[key]);
}
You can also initialize the object using properties, like this:
person.name = "Tom";
person.age = 15;
You can also use JavaScript object literal syntax:
var person = { name: "Tom", age: 15 };
This will work in your simple example scenario:
for (var key in array) {
alert(key + " = " + array[key]);
}
For general use, it's recommended that you test to be sure that the property hasn't been grafted onto the object somewhere else in the inheritance chain:
for (var key in array) {
if (array.hasOwnProperty(key)) {
alert(key + " = " + array[key]);
}
}
Use a javascript object
var object = {};
object.name = "Tom";
object.age = 15;
for ( var i in object ) {
console.log(i+' = '+ object[i]);
}
First, you don't want an array, you want an object. PHP's idea of what constitutes an array is frankly a little weird.
var stuff = {
name: "Tom",
age: 15
};
/* Note: you could also have done
var stuff = {};
stuff.name = "Tom";
stuff.age = 15;
// or
var stuff = {};
stuff["name"] = "Tom";
stuff["age"] = 15;
*/
for (var key in stuff) {
alert(key + " = " + stuff[key];
}