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views:

499

answers:

2

I'm trying to define a system call that modifies the character buffer passed to it. Specifically, something like this:

...
asmlinkage int sys_mycall( char __user *buff, int len )
{
   char tmp[1000];
   copy_from_user(tmp, buff, len);
   /* change tmp here */
   copy_to_user( buff, &tmp, len );
}

Here, copy_to_user returns -1, and the buffer from the calling program is unchanged. What's happening?

+3  A: 

That looks OK. It's possible that the buffer that userspace passed is mapped read-only - for example if it's in the text segment (eg. a string literal). By the way, this is probably what you want:

return copy_to_user(buff, &tmp, len) ? -EFAULT : 0;
caf
The actual code does do that. I simplified the example to illustrate the core issue.
Stefan Kendall
I abhor C. Your answer fully solves my problem, but I refuse to admit why.
Stefan Kendall
I think someone forgot to sign their errno :)
Tim Post
A: 

Remeber that tmp is already a pointer! Correct way to do it:

copy_to_user( buff, tmp, len );
Alex