I have a function that wraps a call to one of my socket types. If there is an error, I want to be able to print a warning and retry. In the warning, I want to have the method name. However, it was declared as a lambda. Is this even possible?
How I call the function (assume in function called myMain):
SafeSocketCommand(() => this.mySocket.ReadCurrentBuffer());
Basic wrapping function:
protected TResult SafeSocketCommand<TResult>(Func<TResult> socketCommand)
{
TResult retValue = default(TResult);
try
{
retValue = socketCommand();
}
catch (PacketLost)
{
ReportToLogs("Timeout on command '" + socketCommand.Method.Name);
}
return retValue;
}
But socketCommand.Method.Name gives me the calling method (from the Stack Trace?) '< myMain >b__3' and I want the actual function being invoked by socketCommand (mySocket.ReadCurrentBuffer). Is it possible to get this information anywhere, or is it lost due to declaring in a lambda?
EDIT:
I should have mentioned that I use this particular calling convention so that I can use socket based commands of various signatures.
int i = SafeSocketCommand(() => this.mySocket.FunctionReturnsInt())
bool b = SafeSocketCommand(() => this.mySocket.FunctionReturnsBool(string s))
object o = SafeSocketCommand(() => this.mySocket.Complicated(string s, int i, bool b))
It also handles no return type signatures by overloading:
protected void SafeSocketCommand(Action socketCommand)
{
SafeSocketCommand(() => { socketCommand(); return 0; });
}