views:

230

answers:

2

Is there a fast way of checking if an object is a jQuery object or a native javascript object?

example:

var o = {};
var e = $('#element');

function doStuff(o) {
    if (o.selector) {
        console.log('object is jQuery');
    }
}

doStuff(o);
doStuff(e);

obviously, the code above works but it's not safe. You could potentially add a selector key to the o and get the same result. Is ther a better way of making sure that the object actually is a jQuery object?

Something in the line of (typeof obj == 'jquery')

+17  A: 

You can use the instanceof operator:

obj instanceof jQuery

Explanation: the jQuery function (aka $) is implemented as a constructor function. Constructor functions are to be called with the new prefix.

When you call $(foo), internally jQuery translates this to new jQuery(foo)1. JavaScript proceeds to initialize this inside the constructor function to point to a new instance of jQuery, setting it's properties to those found on jQuery.prototype (aka jQuery.fn). Thus, you get a new object where instanceof jQuery is true.


1It's actually new jQuery.prototype.init(foo): the constructor logic has been offloaded to another constructor function called init, but the concept is the same.

Crescent Fresh
+2  A: 

Check out the instanceof operator.

var isJqueryObject = obj instanceof jQuery
Corey Sunwold