Jquery - How to get the style display attribute "none / block"

Question

Is there a way to get the style: display attribute which would have either none or block?

DIV :

<div id="ctl00_MainContentAreaPlaceHolder_cellPhone_input_msg_container" class="Error cellphone" style="display: block;">

     <p class="cellphone" style="display: block;">Text</p>

</div>

I know that there is a way to find out if the DIV is hidden or not but in my case this div is dynamically injected so it always shows up as visible false thus I cannot use that :

$j('.Error .cellphone').is(':hidden')

I am aable to get the result "display:block" using :

$j('div.contextualError.ckgcellphone').attr('style')

Is there a way to get just the value "block" or "none" or if theres a better/more efficient way to do this?

Answer 1

You could try:

$j('div.contextualError.ckgcellphone').css('display')

Answer 2

gnarf, big thnx!