Get first day of week in PHP?

Question

Given a date MM-dd-yyyy format, can someone help me get the first day of the week?

Answer 1

Try this:

function week_start_date($wk_num, $yr, $first = 1, $format = 'F d, Y')
{
    $wk_ts  = strtotime('+' . $wk_num . ' weeks', strtotime($yr . '0101'));
    $mon_ts = strtotime('-' . date('w', $wk_ts) + $first . ' days', $wk_ts);
    return date($format, $mon_ts);
}

$sStartDate = week_start_date($week_number, $year);
$sEndDate   = date('F d, Y', strtotime('+6 days', strtotime($sStartDate)));

(from this forum thread)

Answer 2

You parse the date using strptime() and use date() on the result:

date('N', strptime('%m-%d-%g', $dateString));

Answer 3

$givenday = date("w", mktime(0, 0, 0, MM, dd, yyyy));

This gives you the day of the week of the given date itself where 0 = Sunday and 6 = Saturday. From there you can simply calculate backwards to the day you want.

Answer 4

<?php
/* PHP 5.3.0 */

date_default_timezone_set('America/Denver'); //Set apprpriate timezone
$start_date = strtotime('2009-12-15'); //Set start date

//Today's date if $start_date is a Sunday, otherwise date of previous Sunday
$today_or_previous_sunday = mktime(0, 0, 0, date('m', $start_date), date('d', $start_date), date('Y', $start_date)) - ((date("w", $start_date) ==0) ? 0 : (86400 * date("w", $start_date)));

//prints 12-13-2009 (month-day-year)
echo date('m-d-Y', $today_or_previous_sunday);

?>

(Note: MM, dd and yyyy in the Question are not standard php date format syntax - I can't be sure what is meant, so I set the $start_date with ISO year-month-day)

Answer 5

echo strtotime("last sunday", strtotime("MM-dd-yyyy"));