views:

507

answers:

2

I have this code:

$.ajax({
        url : url,
        data : {ids : JSON.stringify(jsonids), hotel_id: hotel_id},
        success : function(response)
        {
            $('#be-images ul').prepend(response).fadeIn('slow');
        },
        dataType: 'html'
    });

but the fade In does not work...I want the content to be prepended and faded in...how will I do this?

Thanks in advance!

+7  A: 

Assuming response is HTML then try this:

$(response).hide().prependTo("#be-images ul").fadeIn("slow");

When you do it this way:

$('#be-images ul').prepend(response).fadeIn('slow');

the thing you're actually fading in is the result of the initial selector (the list at the front), which is already visible.

cletus
working perfectly! thanks!
Ygam
+1  A: 

+1 to cletus, but I just wanted to highlight the other way you could do it.

$('#be-images ul').prepend(
    $(response).hide().fadeIn('slow')
);
nickf
+1 interesting. I've never seen it done that way.
cletus