views:

65

answers:

3

I am allowing to make a new field in one of my web apps, to add a product.

Pushing add a product clones one of the inputs, and I set it to a blank value.

I need to update the name however. The name is in this format

<input type="text" name="product[0][0][3][title]" value="my product" id="input-AbGHtQS3" maxlength="150" />

I need to increment the last numerical index, that is the 3 in this example.

I wrote a regex to match the character, but I must be having a bad day, as I can't come up with something to increment that last number.

Here is my regex:

/^product\[\d+\]\[\d+\]\[(\d+)\]\[.+\]/

How could I increment that last number?

+4  A: 

from: http://stackoverflow.com/questions/423107/use-regexp-to-match-a-parenthetical-number-then-increment-it

The replace method can take a function as its second argument. It gets the match (including submatches) and returns the replacement string. Others have already mentioned that the parentheses need to be escaped.

"Item Name (4)".replace(/\((\d+)\)/, function(fullMatch, n) {
    return "(" + (Number(n) + 1) + ")";
});

So,

*edit:

this should work

"product[0][0][3][title]".replace(/(^product\[\d+\]\[\d+\]\[)(\d+)(\]\[.+\])/, function(fullMatch, n, a, o) {
    return n + (Number(a) + 1) + o;
});
Andrew Mcveigh
Didn't know you could give an anonymous function as 2nd argument! Learn something new every day. Thanks a bunch, will implement now.
alex
Couldn't get it to work - see http://jsbin.com/obila/edit it is returning 4 - is that correct? How would I then make the name attribute read correctly? i.e. 'product[0][0][4][title]'
alex
Ah crap, it's replacing the whole match. I'll give it another try.
Andrew Mcveigh
@Andrew Thanks so much
alex
Andrew Mcveigh
+1  A: 

A more iterative approach:

r = /^(product\[\d+\]\[\d+\]\[)(\d+)(\]\[[a-z]+\])$/;
m = s.match(r);
if (!m) { /* do something smart; */ }
s.replace(r, "$1" + (Number(m[2]) + 1) + "$3");

I added a capture group at the head and tail of your regex. Then match, increment, and reassemble the string.

+1 for the match function on the regex though, I didn't know that trick.

Seth
+1  A: 

Based on Andrew's answer, but corrected to return entire string:

"product[0][0][3][title]".replace (
    /^(product\[\d+\]\[\d+\]\[)(\d+)(\]\[.+\])/,
    function(fullMatch, pre, n, post) {
        return pre + (Number(n) + 1) + post;
    }
);
K Prime
didn't see your answer before i edited, sorry. +1
Andrew Mcveigh