views:

239

answers:

9

Short Version

For those who don't have the time to read my reasoning for this question below:

Is there any way to enforce a policy of "new objects only" or "existing objects only" for a method's parameters?

Long Version

There are plenty of methods which take objects as parameters, and it doesn't matter whether the method has the object "all to itself" or not. For instance:

var people = new List<Person>();

Person bob = new Person("Bob");

people.Add(bob);
people.Add(new Person("Larry"));

Here the List<Person>.Add method has taken an "existing" Person (Bob) as well as a "new" Person (Larry), and the list contains both items. Bob can be accessed as either bob or people[0]. Larry can be accessed as people[1] and, if desired, cached and accessed as larry (or whatever) thereafter.

OK, fine. But sometimes a method really shouldn't be passed a new object. Take, for example, Array.Sort<T>. The following doesn't make a whole lot of sense:

Array.Sort<int>(new int[] {5, 6, 3, 7, 2, 1});

All the above code does is take a new array, sort it, and then forget it (as its reference count reaches zero after Array.Sort<int> exits and the sorted array will therefore be garbage collected, if I'm not mistaken). So Array.Sort<T> expects an "existing" array as its argument.

There are conceivably other methods which may expect "new" objects (though I would generally think that to have such an expectation would be a design mistake). An imperfect example would be this:

DataTable firstTable = myDataSet.Tables["FirstTable"];
DataTable secondTable = myDataSet.Tables["SecondTable"];

firstTable.Rows.Add(secondTable.Rows[0]);

As I said, this isn't a great example, since DataRowCollection.Add doesn't actually expect a new DataRow, exactly; but it does expect a DataRow that doesn't already belong to a DataTable. So the last line in the code above won't work; it needs to be:

firstTable.ImportRow(secondTable.Rows[0]);

Anyway, this is a lot of setup for my question, which is: is there any way to enforce a policy of "new objects only" or "existing objects only" for a method's parameters, either in its definition (perhaps by some custom attributes I'm not aware of) or within the method itself (perhaps by reflection, though I'd probably shy away from this even if it were available)?

If not, any interesting ideas as to how to possibly accomplish this would be more than welcome. For instance I suppose if there were some way to get the GC's reference count for a given object, you could tell right away at the start of a method whether you've received a new object or not (assuming you're dealing with reference types, of course--which is the only scenario to which this question is relevant anyway).


EDIT:

The longer version gets longer.

All right, suppose I have some method that I want to optionally accept a TextWriter to output its progress or what-have-you:

static void TryDoSomething(TextWriter output) {
    // do something...
    if (output != null)
        output.WriteLine("Did something...");

    // do something else...
    if (output != null)
        output.WriteLine("Did something else...");

    // etc. etc.

    if (output != null)
        // do I call output.Close() or not?
}

static void TryDoSomething() {
    TryDoSomething(null);
}

Now, let's consider two different ways I could call this method:

string path = GetFilePath();
using (StreamWriter writer = new StreamWriter(path)) {
    TryDoSomething(writer);

    // do more things with writer
}

OR:

TryDoSomething(new StreamWriter(path));

Hmm... it would seem that this poses a problem, doesn't it? I've constructed a StreamWriter, which implements IDisposable, but TryDoSomething isn't going to presume to know whether it has exclusive access to its output argument or not. So the object either gets disposed prematurely (in the first case), or doesn't get disposed at all (in the second case).

I'm not saying this would be a great design, necessarily. Perhaps Josh Stodola is right and this is just a bad idea from the start. Anyway, I asked the question mainly because I was just curious if such a thing were possible. Looks like the answer is: not really.

+11  A: 

No, basically.

There's really no difference between:

var x = new ...;
Foo(x);

and

Foo(new ...);

and indeed sometimes you might convert between the two for debugging purposes.

Note that in the DataRow/DataTable example, there's an alternative approach though - that DataRow can know its parent as part of its state. That's not the same thing as being "new" or not - you could have a "detach" operation for example. Defining conditions in terms of the genuine hard-and-fast state of the object makes a lot more sense than woolly terms such as "new".

Jon Skeet
According to Emily PostNet's rules of object etiquette, a constructor should leave an object fully initialized and ready for use.
Cylon Cat
+6  A: 

No. And if there is some reason that you need to do this, your code has improper architecture.

Josh Stodola
Not saying Microsoft is perfect, but his example is of a Microsoft method that would benefit from such a restriction/attribute:"OK, fine. But sometimes a method really shouldn't be passed a new object. Take, for example, Array.Sort<T>. The following doesn't make a whole lot of sense:"Array.Sort<int>(new int[] {5, 6, 3, 7, 2, 1});
Aequitarum Custos
If it doesn't make a whole lot of sense then why would you write that code? Exactly.
Josh Stodola
Imagine for a second that a function is an automatic car wash. Should it turn me away just because my car is brand new and sparkling clean? Of course not. It has a job to do, and it doesn't care.
Josh Stodola
Why can't I sort a temporary array?
sixlettervariables
@Josh: I wasn't necessarily saying that what I'm asking about would be a great design choice. Mainly I was just wondering if it were possible. That said, I added an example of a method that might seem to make a little more sense than `Array.Sort<int>(new int[] {...})` -- although, really, I suppose it is also rather poorly designed. In the end I think I agree with you.
Dan Tao
+3  A: 

Short answer - no there isn't

In the vast majority of cases I usually find that the issues that you've listed above don't really matter all that much. When they do you could overload a method so that you can accept something else as a parameter instead of the object you are worried about sharing.

// For example create a method that allows you to do this:
people.Add("Larry");

// Instead of this:
people.Add(new Person("Larry"));

// The new method might look a little like this:
public void Add(string name)
{
    Person person = new Person(name);
    this.add(person); // This method could be private if neccessary
}
Kragen
Excellent point.
Dan Tao
A: 

Nope, there's no way of knowing.

All that gets passed in is the object reference. Whether it is 'newed' in-situ, or is sourced from an array, the method in question has no way of knowing how the parameters being passed in have been instantiated and/or where.

Wim Hollebrandse
+4  A: 

Yes, there is a way to do this.

Sort of.

If you make your parameter a ref parameter, you'll have to have an existing variable as your argument. You can't do something like this:

DoSomething(ref new Customer());

If you do, you'll get the error "A ref or out argument must be an assignable variable."

Of course, using ref has other implications. However, if you're the one writing the method, you don't need to worry about them. As long as you don't reassign the ref parameter inside the method, it won't make any difference whether you use ref or not.

I'm not saying it's good style, necessarily. You shouldn't use ref or out unless you really, really need to and have no other way to do what you're doing. But using ref will make what you want to do work.

Kyralessa
I really appreciate that you thought outside the box and offered an idea that would actually "sort of" work, albeit with definite drawbacks (as you admit).
Dan Tao
If you use a ref parameter, the caller can still pass to the function a variable containing an object that has been created right before to call the function. In that way, you have not resolved the problem of knowing if an object has been created right before the call to the function or much time before that; you simply forced developers to not use a call like DoSomething(new Customer()), which is sometimes used when the passed parameter is only used as parameter for the function.
kiamlaluno
the time between creation and use is not really relavant here, if i understand the problem, it is more distinguishing between lvaluses and rvalues, and ref appear to guarantee an lvalue. There appears to be no way to guarantee an rvalue though?
jk
kiamlaluno, everything you've said is correct. But what you've said has little to do with what Dan was asking.
Kyralessa
A: 

As a possible partial solution if you only wanted one of an object to be consumed by a method maybe you could look at a Singleton. In this way the method in question could not create another instance if it existed already.

DiggerMeUp
A: 

One way to know if an object passed to a function (or a method) has been created right before the call to the function/method is that the object has a property that is initialized with the timestamp passed from a system function; in that way, looking at that property, it would be possible to resolve the problem.

Frankly, I would not use such method because

  • I don't see any reason why the code should now if the passed parameter is an object right created, or if it has been created in a different moment.
  • The method I suggest depends from a system function that in some systems could not be present, or that could be less reliable.
  • With the modern CPUs, which are a way faster than the CPUs used 10 years ago, there could be the problem to use the right value for the threshold value to decide when an object has been freshly created, or not.

The other solution would be to use an object property that is set to a a value from the object creator, and that is set to a different value from all the methods of the object.
In this case the problem would be to forget to add the code to change that property in each method.

Once again I would ask to myself "Is there a really need to do this?".

kiamlaluno
+2  A: 

I can think of a way to do this, but I would definitely not recommend this. Just for argument's sake.

What does it mean for an object to be a "new" object? It means there is only one reference keeping it alive. An "existing" object would have more than one reference to it.

With this in mind, look at the following code:

    class Program
    {
        static void Main(string[] args)
        {
            object o = new object();

            Console.WriteLine(IsExistingObject(o));
            Console.WriteLine(IsExistingObject(new object()));

            o.ToString();  // Just something to simulate further usage of o.  If we didn't do this, in a release build, o would be collected by the GC.Collect call in IsExistingObject. (not in a Debug build)
        }

        public static bool IsExistingObject(object o)
        {
            var oRef = new WeakReference(o);

#if DEBUG 
            o = null; // In Debug, we need to set o to null.  This is not necessary in a release build.
#endif
            GC.Collect();
            GC.WaitForPendingFinalizers();

            return oRef.IsAlive;
        }
    }

This prints True on the first line, False on the second. But again, please do not use this in your code.

Geert Baeyaert
Haha, what a beautifully horrendous suggestion. +1 for an answer that actually seems plausible to me, though it is, as you admit, *not* advisable at all.
Dan Tao
It just occurred to me, though, this "useful" little helper would actually be useless if called from *within* another function, since the calling function would still have a reference to the object in question. Which means that rather than `IsExistingObject`, one would need to simply duplicate this code everywhere to use it. Yikes. Good thing it wasn't a serious suggestion in the first place ;)
Dan Tao
+1  A: 

Let me rewrite your question to something shorter.

Is there any way, in my method, which takes an object as an argument, to know if this object will ever be used outside of my method?

And the short answer to that is: No.

Let me venture an opinion at this point: There should not be any such mechanism either.

This would complicate method calls all over the place.

If there was a method where I could, in a method call, tell if the object I'm given would really be used or not, then it's a signal to me, as a developer of that method, to take that into account.

Basically, you'd see this type of code all over the place (hypothetical, since it isn't available/supported:)

if (ReferenceCount(obj) == 1) return; // only reference is the one we have

My opinion is this: If the code that calls your method isn't going to use the object for anything, and there are no side-effects outside of modifying the object, then that code should not exist to begin with.

It's like code that looks like this:

1 + 2;

What does this code do? Well, depending on the C/C++ compiler, it might compile into something that evaluates 1+2. But then what, where is the result stored? Do you use it for anything? No? Then why is that code part of your source code to begin with?

Of course, you could argue that the code is actually a+b;, and the purpose is to ensure that the evaluation of a+b isn't going to throw an exception denoting overflow, but such a case is so diminishingly rare that a special case for it would just mask real problems, and it would be really simple to fix by just assigning it to a temporary variable.

In any case, for any feature in any programming language and/or runtime and/or environment, where a feature isn't available, the reasons for why it isn't available are:

  • It wasn't designed properly
  • It wasn't specified properly
  • It wasn't implemented properly
  • It wasn't tested properly
  • It wasn't documented properly
  • It wasn't prioritized above competing features

All of these are required to get a feature to appear in version X of application Y, be it C# 4.0 or MS Works 7.0.

Lasse V. Karlsen