Using SELECT in this SQL statement isn't working...

Question

My table is organised like this:

With key as the primary field. The records shown are in the renamed table.

I need to get out the original_name by the key. The key coluimn is the primary key of the table.

This is my SQL code:

SELECT original_name FROM `renamed` WHERE key='fb166'

However, it does not return any results. I have tried both through my PHP script and directly through phpMyAdmin and both return an empty result set.

Any help? :/

Answer 1

Try something like

SELECT '|' || key || '|'
FROM renamed
WHERE key LIKE '%fb166%'

and check if you get a result and how the key looks like...

Do you get any results with the following?

SELECT * FROM renamed

Answer 2

key is a reserved word in MySQL. Have you tried:

SELECT original_name FROM `renamed` WHERE `key`='fb166'

Answer 3

1. The backticks are necessary as key is a keyword in mysql.

2. As suggested try with WHERE key LIKE '%fb166%' as you column is of type text it s probably you have some other char in it.

3. It s a bad idea to have a key with a type of text, you will not be able to make it a primary key or add an index to it.