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Answer 1

+2 A:

Whilst a single document can only contain one root element, as XSD can actually define multiple valid root elements.

If you only genuinely want a single type to be valid as a root element, then it should be the only type referenced as an <element>.

In your schema above, for example, the DocumentInfo and Prerequisite nodes are valid root elements too. To restrict your schema to have just a single, valid root node, replace your DocumentInfo and Prerequisite elements with simple complexType definitions:

<xsd:complexType name="DocumentInfoType">
    ...
</xsd:complexType>
<xsd:complexType name="Prerequisite">
    ....
</xsd:complexType>

UPDATE: To access the name of an element, you just need to look at the Name property on the XmlElement:

XmlDocument doc = new XmlDocument();
doc.Load("D:\\schema.xsd");                      // Load the document from the root of an ASP.Net website

XmlElement schemaElement = doc.DocumentElement;  // The root element of the schema document is the <schema> element
string elementName = schemaElement.LocalName;    // This will print "schema"
foreach (XmlNode ele in schemaElement.ChildNodes)
{
    if (ele.LocalName == "element")
    {
        // This is a valid root node
        // Note that there will be *more than one* of these if you have multiple elements declare at the base level
    }
}

Dexter 2009-12-21 03:00:45

Hello. I am programming a xsd file parser script. there is some foreach (find element) lines in my scipt. But i can't read the Value. That's why bothed me a lot. If i referenced as an element. acturally there is several elements in my XSD file.

Nano HE 2009-12-21 03:08:03

@Dexter. from your script above, the xe.Name return "xsd:schema". Suppose the XSD is a XML format file too. The return value is the root element. No doubt. // But i still can't get the root element value :"RootValueHere" Is there any RootElemnt Property for Schema file?

Nano HE 2009-12-21 05:09:32

@Nano - apologies - I've now corrected the code snippet and expanded it a bit further

Dexter 2009-12-21 20:06:13

@Dexter, THANKS a lot!

Nano HE 2009-12-22 00:26:03

Answer 2

+1 A:

I believe

XmlDocument myDocument = new XmlDocument("my.xml");
myDocument.DocumentElement(); //gets root document node

Woot4Moo 2009-12-21 03:04:25

I work together with my team for my project. I handle job of the XSD parse. I must find out the (only one in my XSD file) root element from the XSD file. then generate a list for my team member who could validate the XML file based on my result. (She can't find the root element from my list, and she already could get the XML file with the method you provide above.

Nano HE 2009-12-21 03:13:06

since an XSD is a XmlDocument I don't see how that would fail. However, the only other thing I can think is to use an xpath query

Woot4Moo 2009-12-21 03:23:56

We're talking about two different things here - one is parsing the XSD document, and the other is parsing the XML documents which describe data in the format defined by the XSD - @Nano is talking about parsing the XSD, but validating the XML document

Dexter 2009-12-21 03:32:36

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How to find XSD root element in C#

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