Constructing a python set from a numpy matrix

Question

I'm trying to execute the following

>> from numpy import *
>> x = array([[3,2,3],[4,4,4]])
>> y = set(x)
TypeError: unhashable type: 'numpy.ndarray'

How can I easily and efficiently create a set from a numpy array?

Answer 1

The immutable counterpart to an array is the tuple, hence, try convert the array of arrays into an array of tuples:

>> from numpy import *
>> x = array([[3,2,3],[4,4,4]])

>> x_hashable = map(tuple, x)

>> y = set(x_hashable)
set([(3, 2, 3), (4, 4, 4)])

Answer 2

If you want a set of the elements:

>> y = set(e for r in x
             for e in r)
set([2, 3, 4])

For a set of the rows:

>> y = set(tuple(r) for r in x)
set([(3, 2, 3), (4, 4, 4)])

Answer 3

If you want a set of the elements, here is another, probably faster way:

y = set(x.flatten())

PS: after performing comparisons between x.flat, x.flatten(), and x.ravel() on a 10x100 array, I found out that they all perform at the same speed. For a 3x3 array, the fastest version is the iterator version:

y = set(x.flat)

which I would recommend because it is the less memory expensive version (it scales up well with the size of the array).