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5
+10  Q: 

Call and Callvirt

What is the difference between the CIL instructions "Call" and "Callvirt"?

+11  A: 

call is for calling non-virtual, static, or superclass methods, i.e., the target of the call is not subject to overriding. callvirt is for calling virtual methods (so that if this is a subclass that overrides the method, the subclass version is called instead).

Chris Jester-Young
If I remember correctly `call` doesn't check the pointer against null before performing the call, something which `callvirt` obviously needs to. That is why `callvirt` sometimes is emitted by the compiler even though calling non-virtual methods.
dalle
Ah. Thanks for pointing that out (I'm not a .NET person). The analogies I use are call => invokespecial, and callvirt => invokevirtual, in JVM bytecode. In the case of the JVM, both instructions check "this" for nullness (I just wrote a test program to check).
Chris Jester-Young
You might want to mention the performance difference in your answer, that being the reason for having a 'call' instruction at all.
Nick Johnson
I disagree. Not having a performance difference would not eliminate the raison d'etre of the call (or invokespecial) instruction.
Chris Jester-Young
+13  A: 

When the runtime executes a call instruction it's making a call to an exact piece of code (method). There's no question about where it exists. Once the IL has been JITted, the resulting machine code at the call site is an unconditional jmp instruction.

By contrast, the callvirt instruction is used to call virtual methods in a polymorphic way. The exact location of the method's code must be determined at runtime for each and every invocation. The resulting JITted code involves some indirection through vtable structures. Hence the call is slower to execute, but it is more flexible in that it allows for polymorphic calls.

Note that the compiler can emit call instructions for virtual methods. For example:

sealed class SealedObject : object
{
   public override bool Equals(object o)
   {
      // ...
   }
}

Consider calling code:

SealedObject a = // ...
object b = // ...

bool equal = a.Equals(b);

While System.Object.Equals(object) is a virtual method, in this usage there is no way for an overload of the Equals method to exist. SealedObject is a sealed class and cannot have subclasses.

For this reason, .NET's sealed classes can have better method dispatching performance than their non-sealed counterparts.

EDIT: Turns out I was wrong. The C# compiler cannot make an unconditional jump to the method's location because the object's reference (the value of this within the method) might be null. Instead it emits callvirt which does the null check and throws if required.

This actually explains some bizarre code I found in the .NET framework using Reflector:

if (this==null) // ...

It's possible for a compiler to emit verifiable code that has a null value for the this pointer (local0), only csc doesn't do this.

So I guess call is only used for class static methods and structs.

Given this information it now seems to me that sealed is only useful for API security. I found another question that seems to suggest there are no performance benefits to sealing your classes.

EDIT 2: There's more to this than it seems. For example the following code emits a call instruction:

new SealedObject().Equals("Rubber ducky");

Obviously in such a case there is no chance that the object instance could be null.

Interestingly, in a DEBUG build, the following code emits callvirt:

var o = new SealedObject();
o.Equals("Rubber ducky");

This is because you could set a breakpoint on the second line and modify the value of o. In release builds I imagine the call would be a call rather than callvirt.

Unfortunately my PC is currently out of action, but I'll experiment with this once it's up again.

Drew Noakes
Sealed attributes are definitely faster when looking for them via reflection, but other than that, I don't know of any other benefits you haven't mentioned.
TraumaPony
+6  A: 

For this reason, .NET's sealed classes can have better method dispatching performance than their non-sealed counterparts.

Unfortunately this is not the case. Callvirt does one other thing that makes it useful. When an object has a method called on it callvirt will check if the object exists, and if not throws a NullReferenceException. Call will simply jump to the memory location even if the object reference is not there, and try to execute the bytes in that location.

What this means is that callvirt is always used by the C# compiler (not sure about VB) for classes, and call is always used for structs (because they can never be null or subclassed).

Edit In response to Drew Noakes comment: Yes it seems you can get the compiler to emit a call for any class, but only in the following very specific case:

public class SampleClass
{
    public override bool Equals(object obj)
    {
        if (obj.ToString().Equals("Rubber Ducky", StringComparison.InvariantCultureIgnoreCase))
            return true;

        return base.Equals(obj);
    }

    public void SomeOtherMethod()
    {
    }

    static void Main(string[] args)
    {
        // This will emit a callvirt to System.Object.Equals
        bool test1 = new SampleClass().Equals("Rubber Ducky");

        // This will emit a call to SampleClass.SomeOtherMethod
        new SampleClass().SomeOtherMethod();

        // This will emit a callvirt to System.Object.Equals
        SampleClass temp = new SampleClass();
        bool test2 = temp.Equals("Rubber Ducky");

        // This will emit a callvirt to SampleClass.SomeOtherMethod
        temp.SomeOtherMethod();
    }
}

NOTE The class does not have to be sealed for this to work.

So it looks like the compiler will emit a call if all these things are true:

  • The method call is immediately after the object creation
  • The method is not implemented in a base class
Cameron MacFarland
That makes sense. I had studied CIL and made an assumption about the behaviour of the compiler. Thanks for clearing this up. I'll update my answer.
Drew Noakes
Actually I don't believe you're 100% correct here. I've updated my post (edit 2).
Drew Noakes
Hi Cameron. Can you clarify whether the analysis of this code was performed on a release build?
Drew Noakes
There's no difference between calls in the debug and release builds. The only difference is in the stack manipulation code between calls. CallVirt is used in the first call because it's not calling SampleClass.Equals but Object.Equals.
Cameron MacFarland
A: 
bool test1 = new SampleClass().Equals("Rubber Ducky");

I can't understand why this call is for System.Object.Equals.

When we do the call, the callvirt instruction is emitted and we search the metadata of the type of the reference responsible for the call if this virtual method is overridden. If it is actually overridden, then the call to that "version" is made. Otherwise, it's called the System.Object version.

I'm very confused about this right now, would appreciate a bit of a clarification. Thanks ;)

Bruno
The call to `Object.Equals` is made because that's the site at which the virtual method is defined. If you had a `new` method definition that hid a parent's method, then the emitted call would be for your new method. Does that help clarify?
Drew Noakes
A: 

According to MSDN:

Call:

The call instruction calls the method indicated by the method descriptor passed with the instruction. The method descriptor is a metadata token that indicates the method to call...The metadata token carries sufficient information to determine whether the call is to a static method, an instance method, a virtual method, or a global function. In all of these cases the destination address is determined entirely from the method descriptor (contrast this with the Callvirt instruction for calling virtual methods, where the destination address also depends upon the runtime type of the instance reference pushed before the Callvirt).

CallVirt:

The callvirt instruction calls a late-bound method on an object. That is, the method is chosen based on the runtime type of obj rather than the compile-time class visible in the method pointer. Callvirt can be used to call both virtual and instance methods.

So basically, different routes are taken to invoke an object's instance method, overriden or not:

Call: variable -> variable's type object -> method

CallVirt: variable -> object instance -> object's type object -> method

smwikipedia