in C, what is the proper way to define a printf like macro that will print only when DEBUG symbol is defined?
#ifdef DEBUG
#define DEBUG_PRINT(???) ???
#else
#define DEBUG_PRINT(???) ???
#endif
where ??? is where I am not sure what to fill in
in C, what is the proper way to define a printf like macro that will print only when DEBUG symbol is defined?
#ifdef DEBUG
#define DEBUG_PRINT(???) ???
#else
#define DEBUG_PRINT(???) ???
#endif
where ??? is where I am not sure what to fill in
Something like:
#ifdef DEBUG
#define DEBUG_PRINT(fmt, args...) fprintf(stderr, fmt, ## args)
#else
#define DEBUG_PRINT(fmt, args...) /* Don't do anything in release builds */
#endif
#ifdef DEBUG
#define DEBUG_PRINT(...) do{ fprintf( stderr, __VA_ARGS__ ); } while( false )
#else
#define DEBUG_PRINT(...) do{ } while ( false )
#endif
I've seen this idiom a fair amount:
#ifdef DEBUG
# define DEBUG_PRINT(x) printf x
#else
# define DEBUG_PRINT(x) do {} while (0)
#endif
Use it like:
DEBUG_PRINT(("var1: %d; var2: %d; str: %s\n", var1, var2, str));
The extra parentheses are necessary, because some older C compilers don't support var-args in macros.