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146

answers:

1

I am trying to do this:

 {% for movie in movie_list | sort(movie.rating) %}

But that's not right...the documentation is vague...how do you do this in Jinja2?

+3  A: 

Usually we sort the list before giving it to Jinja2. There's no way to specify a key in Jinja's sort filter.

However, you can always try {% for movie in movie_list|sort %}. That's the syntax. You don't get to provide any sort of key information for the sorting.

You can also try and write a custom filter for this. Seems silly when you can sort before giving the data to Jinja2.

If movie_list is a list of objects, then you can define the various comparison methods (__lt__, __gt__, etc.) for the class of those objects.

If movie_list is a list of tuples or lists, the rating must be first. Or you'll have to do the sorting outside Jinja2.

If movie_list is a list of dictionaries, then you can use dictsort, which does accept a key specification for the sorting. Read this: http://jinja.pocoo.org/2/documentation/templates#dictsort for an example.

S.Lott
Ok, thanks.I did end up sorting in Python before sending to template:<code>movie_list = sorted( movie_list, key = lambda movie:movie.rating, reverse = True )</code>Too bad, it might be nice to let the template decide on the sort order!( could other template engines do this? )
Nick Perkins