views:

232

answers:

2

Hi,

I have some div´s in my page (build with php+jquery) and I want to filter them according to their attributes (if there´s more than 1 attribute filtering, than it will narrow down the search). The div´s look like this:

<div id="solicitacoes">
    <div id='1' title='Mike' status='18' analista='23'>Whatever content 1</div>
    <div id='2' title='John' status='16' analista='46'>Whatever content 2</div>
    <div id='3' title='Tom' status='2' analista='49'>Whatever content 3</div>
    <div id='4' title='Mike' status='4' analista='23'>Whatever content 4</div>
    <div id='5' title='Kate' status='3' analista='32'>Whatever content 5</div>
    <div id='6' title='Steve' status='1' analista='14'>Whatever content 6</div>
</div>

Then, I have a form to filter the div´s attributes:

<div id="filtros">
<form id="filtroSolicitacoes" type="post" name="filtroSolicitacoes">
Protocolo: <input type="text" name="filtroProtocolo" id="filtroProtocolo" size="5"/>
Solicitante: <input type="text" name="filtroSolicitante" id="filtroSolicitante" size="10"/>
Status: 
<select name="filtroStatus" id="filtroStatus">
<option value="0">-- Selecione Status--</option>
<option value="3">Aguardando Aprova&ccedil;&atilde;o</option>
<option value="18">Encaminhado</option>
<option value="2">Iniciado</option>
<option value="1">N&atilde;o Iniciado</option>
<option value="4">Pendente de Esclarecimento</option>
<option value="16">Reiniciado</option>
<option value="6">Reprovado</option>
</select>
Analista: 
<select name="filtroAnalista" id="filtroAnalista">
    <option value="23">Robert</option>
    <option value="46">Allan</option>
    <option value="49">Edward</option>
    <option value="32">Jake</option>
    <option value="14">Stella</option>
</select>
<button type="submit" id="filtrar" style="float:right; margin-right:10px">:: Filtrar ::</button>
</form>
</div>

Now, I´ve alredy done most of the Jquery part and the filter is working ---> But I want to NARROW DOWN the search if there´s more than 1 filtering attribute, NOT to concatenate it, and that´s what´s happening with my code bellow:

$("#filtroSolicitacoes").submit(function() {
    $("#solicitacoes > div").show();
    var filtroProtocolo = $("#filtroProtocolo").val();
    var filtroSolicitante = $("#filtroSolicitante").val().toUpperCase();
    var filtroStatus = $("#filtroStatus").val();
    var filtroAnalista = $("#filtroAnalista").val();
    var filtroResultado = $("#filtroResultado:checked").length;

    var filtros = "[id=filtros]";

    if(filtroStatus !== "0"){
        filtros +=",[status='"+filtroStatus+"']";
    }
    if(filtroProtocolo !== ""){
        filtros +=",[id='"+filtroProtocolo+"']";
    }
    if(filtroSolicitante !== ""){
        filtros +=",[title*='"+filtroSolicitante+"']";
    }
    if(filtroAnalista !== "0"){
        filtros +=",[analista='"+filtroAnalista+"']";
    }

    if(filtros !== "[id=filtros]"){
        $("#solicitacoes > div:not("+filtros+")").hide();
    }
    return false;
});

I´ve tried to use "&&" instead of "," in

filtros +=",[analista='"+filtroAnalista+"']";

But it didn´t work.

any ideas?

PS: Sorry for my poor English, I´m brazilian :)

A: 

Just remove the commas.

So instead of:

filtros +=",[status='"+filtroStatus+"']";

Use

filtros +="[status='"+filtroStatus+"']";

You want your resulting query to look like this:

"[status=status][title*='whatever']"

Also, the way you are calling it isn't filtering it correctly. This is how I would change your function to make it work (You can view a working demo of your code, and play with it.):

$("#filtroSolicitacoes").submit(function() {
    var filtroProtocolo = $("#filtroProtocolo").val();
    var filtroSolicitante = $("#filtroSolicitante").val().toUpperCase();
    var filtroStatus = $("#filtroStatus").val();
    var filtroAnalista = $("#filtroAnalista").val();
    var filtroResultado = $("#filtroResultado:checked").length;

    var filtros = "";

    if(filtroStatus !== "0"){
        filtros +="[status='"+filtroStatus+"']";
    }
    if(filtroProtocolo !== ""){
        filtros +="[id='"+filtroProtocolo+"']";
    }
    if(filtroSolicitante !== ""){
        filtros +="[title*='"+filtroSolicitante+"']";
    }
    if(filtroAnalista !== "0"){
        filtros +="[analista='"+filtroAnalista+"']";
    }

    if(filtros !== ""){
        $("#solicitacoes > div").hide().filter(filtros).show();
    } else {
        $("#solicitacoes > div").show();
    }
    return false;
});
Doug Neiner
Hummm... I´ve tried this, but it also concatenated it...
Let your EGO at the door
@Let I updated my answer... sorry didn't notice the use of `not` the first time through. I also added a working demo of the finished code using JSBin.
Doug Neiner
Thank´s Doug... both your solutions work fine!
Let your EGO at the door
+1  A: 

You should use the filter() function:

var filteredList = elements
                      .filter("[status=status1]")
                      .filter("[title*=something]");
// and so on

In your example:

$("#filtroSolicitacoes").submit(function() {
    $("#solicitacoes > div").show();
    var filtroProtocolo = $("#filtroProtocolo").val();
    var filtroSolicitante = $("#filtroSolicitante").val().toUpperCase();
    var filtroStatus = $("#filtroStatus").val();
    var filtroAnalista = $("#filtroAnalista").val();
    var filtroResultado = $("#filtroResultado:checked").length;

    var elements = $("[id=filtros]");

    if(filtroStatus !== "0"){
        elements = elements.filter("[status='"+filtroStatus+"']");
    }
    if(filtroProtocolo !== ""){
        elements = elements.filter("[id='"+filtroProtocolo+"']");
    }

    // and so on

    $("#solicitatcoes > div").not(elements).hide();

    return false;
});
Philippe Leybaert
Idiotic question (I know, so forgive me in advance):The filter function works the other way around, so the var filteredList would be the div´s that I want to show, right? So I would just replace it here? $("#solicitacoes > div:not("+filtros+")").hide();>> $("#solicitacoes > div:not("+filteredList +")").hide();
Let your EGO at the door
Thank´s Philippe!!!!!!!!!!!!!!
Let your EGO at the door