Call a Messagebox.Show() from PowerShell with more than default button?

Answer 1

Try this way:

[windows.forms.messagebox]::show('body','title','YesNo')

And the distinction between using :: and . is static method vs instance method. Notice above that we didn't create a MessageBox object. We are just using a static method on MessageBox with the :: syntax.

Answer 2

Correct way of doing this can be

$buttons=[system.windows.forms.messageboxbuttons]::yesno;
[system.windows.forms.messagebox]::Show("Are you sure?","",$buttons);

Notice "::" instead of "." in the first line. YesNo value is defined staticly on System.Windows.Forms.Messageboxbuttons, so you must use "::" (static call) instead of "."

Note that "[system.windows.forms.messageboxbuttons].yesno" is an attempt to call a "YesNo" property on an instance of System.Type, which does not exist and therefore result in a $null

Hope it helps !

Cédric

Edit ---

Keith solution using an implicit cast made by powershell for the enum is more elegant. It just does not work on PS V2 CTP 3 which I still use but work fine on RTM version. The complete explication was worth giving, though...