Haskell -- How to split a number into a list for further processing?

Question

I have an Int that i want to split into it's individual numbers which ideally would be contained in a list, which i can then process further. So i would like something like this:

split 245
--will then get an list containing [2,4,5]

Is anyone familiar with such a function?

Answer 1

import Data.Char

map digitToInt $ show 245

Answer 2

would the example here work for you ? http://snippets.dzone.com/posts/show/5961

convRadix :: (Integral b) => b -> b -> [b]
convRadix n = unfoldr (\b -> if b == 0 then Nothing else Just (b `mod` n, b `div` n))

example:

> convRadix 10 1234
[4, 3, 2, 1]
> convRadix 10 0
[]
> convRadix 10 (-1)
[9,9,...] (infinite)

to convert haskell radix by mokehehe on Thu Aug 21 08:11:39 -0400 2008

Answer 3

digits :: (Integral a) => a -> [a]
digits = flip digits' [] . abs

digits' :: (Integral a) => a -> ([a] -> [a])
digits' n = if q == 0
  then (r :)
  else (digits q ++) . (r :)
  where
    (q, r) = n `divMod` 10

---

digits   1234  == [1, 2, 3, 4]
digits (-1234) == [1, 2, 3, 4]