You should be able to achieve this with a "lazy" (compared to the default "greedy") ?. Try this:
Regex regex = new Regex(@"(?<g1>a?)(?<g2>a?)(?<g3>b??)(?<g4>b?)");
Lucero
2010-01-18 11:20:30
+2
A:
But there appeared another problem. If this regular expression is applied to 'aabb' I get g1 -> 'a', g2 -> 'a', g3 -> '', g4 -> 'b';but not g1 -> 'a', g2 -> 'a', g3 -> 'b', g4 -> 'b'. I need the second variant.
StuffHappens
2010-01-18 12:00:33
@Stuff - use `^(?<g1>a?)(?<g2>a?)(?<g3>b??)(?<g4>b?)$` . You're allowing the regex to capture a part of your string.
Kobi
2010-01-18 12:23:40
Thanks Kobi, that's what I would have suiggested to Stuff also.
Lucero
2010-01-18 14:11:26