Identifying a certain node in XML

Question

<enviNFe versao="1.10">
  <idLote>000000000000094</idLote> 
  <NFe>
    <infNFe Id="NFe35090254517628000198550010000000011870030005" versao="1.10">
    <!-- ... content ... -->
    </infNFe>
    <Signature xmlns="http://www.w3.org/2000/09/xmldsig#"&gt;
    <!-- ... content ... -->
    </Signature>
  </NFe>
</enviNFe>

I have this XML file, how do i get the ID attribute? this question is not about "how to get attributes in xml's", i've found several solutions, but somehow i can't address to this specific attribute in this specific node.

i can get info inside tables that are within "infNF" and i'm loading it into a dataset and using this code:

ds.Tables(Table).Rows(row)(node)

is there a similar way to do what i want to get THIS attribute ?

(you can answer either in C# or VB.NET)

Answer 1

Have you tried XQuery?

 var node = element.SelectSingleNode("//infNFe[@id='...']")

And by the looks of the XML it appears you're dealing with Brazilian NFe, right?

---

Edited to Add

You can find more about XQuery here.

Once you past the brackets... you'll see it's quite simple.

Answer 2

If you have .Net 3.5 then use linq see http://stackoverflow.com/questions/594231/how-to-select-a-specific-node-with-linq-to-xml

Answer 3

ds.Tables("infNFe").Rows(0).Item(2)

That's what i've used, thank you guys!