views:

81

answers:

3

Hi, I have a table in mySQL and has 3 line which has name ,address,Telephone,Age,Charge. in two of them the names are "Adam" and the last row is "Abas" ,i don't know that why it prints in the console like this,please help me thanks!

      Statement s;
    int s4,s5;String s1,s2,s3;
    List<InfoClass> clientList = null;
    try {
        s = conn.createStatement();
        ResultSet rs = s.executeQuery("SELECT * FROM customer_info WHERE Name LIKE 'A%'");
        InfoClass list = null;

        while (rs.next()) {
            s1 = rs.getString(2);
            if (rs.wasNull()) {
                s1 = null;
            }
            s2 = rs.getString(3);
            if (rs.wasNull()) {
                s2 = null;
            }

            s3 = rs.getString(4);
            if (rs.wasNull()) {
                s3 = null;
            }
              s4 = rs.getInt(5);
            if (rs.wasNull()) {
                s4 = 0;
            }
            s5 = rs.getInt(6);
            if (rs.wasNull()) {
                s5 = 0;
            }





            list = new InfoClass(s1, s2);

            if (clientList == null) {
                clientList = new ArrayList<InfoClass>();
            }

            clientList.add(list);





        }
       for(int i=0;i<clientList.size();i++){
           InfoClass c =clientList.get(i);
           System.out.println(c.getName());


        }

in the console:

run:
Adam Smit
Adam Smit
Abas
Adam Smit
Adam Smit
Adam Smit
Adam Smit

I want the output be like this:

  run:
Adam Smit
Adam Smit
Abas
A: 

You seem to have a customer named 'Abas' in your database, which is a valid match for your query.

soulmerge
A: 

It is better to use the rs.getString( String columnLabel ) method.

Waverick
A: 

Could you please change the println row into this:

System.out.println("" + i + ": " + c.getName());

and run it?

Quassnoi
it works well know,thanks a lot but what was problem?
Johanna
`@Johanna`: what does it output?
Quassnoi