Handling a Python exception that occurs within an except clause

Question

I have some code in a Python except clause that is intended to do some logging, but the logging code might itself cause an exception. In my case, I'd like to just ignore any second exception that might occur, and raise the original exception. Here is a very simplified example:

try:
    a = this_variable_doesnt_exist
except:
    try:
        1/0
    except:
        pass
    raise

Running the above code, I hope to get:

NameError: name 'this_variable_doesnt_exist' is not defined

but instead, in Python 2.x, I get:

ZeroDivisionError: integer division or modulo by zero

I've discovered that in Python 3.x, it does what I want.

I couldn't find much commentary on this in the Python 2.x docs (unless I missed it). Can I achieve this in 2.x?

Answer 1

With abstraction:

def log_it():
    try:
        1 / 0
    except:
        pass

try:
    this = that
except:
    log_it()
    raise

Does what you want in Python 2.5

Another way to do it is to store the exception in a variable, then re-raise it explicitly:

try:
    this = that
except NameError, e: # or NameError as e for Python 2.6
    try:
        1 / 0
    except:
        pass
    raise e

Note that you probably shouldn't just be using a bare except to catch everything that might come - it's usually best to catch the specific exceptions you expect to occur in case a drastic and fatal exception (like being out of memory) occurs.