views:

145

answers:

4

How does:

    1 +   2 + ... + N-1 +   N
 +  N + N-1 + ... +   2 +   1
  ---------------------------
 N+1 + N+1 + ... + N+1 + N+1

equal N(N + 1)? Shouldn't it be 4N + 4 or 4(N + 1)?

+4  A: 

If N is 4, sure. Otherwise you need to fill in the rest of the elided values that the ellipses represent.

Ignacio Vazquez-Abrams
+8  A: 

It is N(N + 1).

Because you have N number of (N+1) terms.

Upul
Oh my god, that is the most elegant answer i've ever seen. Well done. +1
Ian Boyd
+3  A: 

i assume your notation means row 1 + row 2 = row 3?

in this case, look at the columns. Each column of the first 2 rows adds up to n+1. there are n columns. thus row 1 + row 2 = n*(n+1)

Carsten
+2  A: 

Read the part about the early years of Carl Friederich Gauss here. He solved almost the same problem when he was in primary school.

Doc Brown
A similar but different question, actually.
Beska
Ok, I edited my answer a little bit.
Doc Brown