Open a PyGTK program but do not activate it

Question

I have a PyGTK program which is hidden most of the time, but with a keypress it shall come up as a popup. Therefore I want the program not to be activated when its opened. I tried several options to to that, with no success:

self.window.show()

self.window.set_focus(None)

Activates the program, but sets no focus.

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self.window.set_accept_focus(False)

self.window.show()

self.window.set_accept_focus(True)

With the last command, the window gets activated.

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self.window.show()

self.window.unset_flags(gtk.HAS_FOCUS)

Does nothing...

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Btw. I am using Ubuntu 9.10 (metacity)

Answer 1

Build the window but don't call show() on it until it is ready to be activated. Then use self.window.present().

EDIT: If you never want the window to be activated, why not try a notification popup? You need libnotify for this. There are Python bindings. Here is an example: http://roscidus.com/desktop/node/336

In combination with a toolbar applet, this could do what you want -- i.e. the notification is raised when the user either clicks on the applet or presses the key combination.

Answer 2

I figured out how to do it. See the example below:

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#!/usr/bin/env python

import pygtk
pygtk.require('2.0')
import gtk
import gobject

class HelloWorld:
    window=None
    def hello(self, widget, data=None, data2=None):
    HelloWorld.window.set_accept_focus(True)
    HelloWorld.window.present()

    def __init__(self):
        HelloWorld.window = gtk.Window(gtk.WINDOW_TOPLEVEL)
        self.button = gtk.Entry(50)
        self.button.connect("focus-in-event", self.hello, None)
        HelloWorld.window.add(self.button)
        self.button.show()
    HelloWorld.window.set_accept_focus(False)
    self.button.connect('button-press-event', self.hello)
    HelloWorld.window.show()
    def main(self):
        gtk.main()

if __name__ == "__main__":
    hello = HelloWorld()
    hello.main()