Regex Quoted String with Escaped Quotes in C#

Question

I'm trying to find all of the quoted text on a single line.

Example:

"Some Text", and "Some more Text" and "Even more text about \"this text\""

I need to get:

• "Some Text"
• "Some more Text"
• "Even more text about \"this text\""

\"[^\"\r]*\" gives me everything except for the last one, because of the escaped quotes.

I have read about \"[^\"\\]*(?:\\.[^\"\\]*)*\" working, but I get an error at runtime

parsing ""[^"\]*(?:\.[^"\]*)*"" - Unterminated [] set.

Answer 1

I know this isn't the cleanest method but with your example i would check the character before the " to see of its a \ if it is I would ignore the quote.

Answer 2

This works correctly in Expresso: You might need to convert \\ to \\\\ depending on your language

 "(\\"|[^"])*"

Answer 3

Any chance you need to do: \"[^\"\\\\]*(?:\\.[^\"\\\\]*)*\"

Answer 4

"(\\"|\\\\|[^"])*"

should work. Match either an escaped quote, an escaped backslash, or any other character except a quote character. Repeat.

In C#:

StringCollection resultList = new StringCollection();
Regex regexObj = new Regex(@"""(\\""|\\\\|[^""])*""");
Match matchResult = regexObj.Match(subjectString);
while (matchResult.Success) {
    resultList.Add(matchResult.Value);
    matchResult = matchResult.NextMatch();
} 

Edit: Added escaped backslash to the list to correctly handle "This is a test\\".

Explanation:

First match a quote character.

Then the alternatives are evaluated from left to right. The engine first tries to match an escaped quote. If that doesn't match, it tries an escaped backslash. That way, it can distinguish between "Hello \" string continues" and "String ends here \\".

If either don't match, then anything else is allowed except for a quote character. Then repeat.

Finally, match the closing quote.

Answer 5

I recommend getting RegExBuddy.

http://www.regexbuddy.com/

It lets you play around with it until you make sure everything in your test set matches.

As for your problem, I would try 4 /'s instead of two...

\"[^\"\\\\]*(?:\\.[^\"\\\\]*)*\"

Answer 6

This regex

(?<!\\)".*?(?<!\\)"

will also handle text that start with escaped quote:

\"Some Text\" Some Text "Some Text", and "Some more Text" an""d "Even more text about \"this text\""

Answer 7

What you've got there is an example of Friedl's "unrolled loop" technique, but you seem to have some confusion about how to express it as a string literal. Here's how it should look to the regex compiler:

"[^"\\]*(?:\\.[^"\\]*)*"

The initial "[^"\\]* matches a quotation mark followed by zero or more of any characters other than quotation marks or backslashes. That part alone, along with the final ", will match a simple quoted string with no embedded escape sequences, like "this" or "".

If it does encounter a backslash, \\. consumes the backslash and whatever follows it, and [^"\\]* (again) consumes everything up to the next backslash or quotation mark. That part gets repeated as many times as necessary until an unescaped quotation mark turns up (or it reaches the end of the string and the match attempt fails).

Note that this will match "foo\"- in \"foo\"-"bar". That may seem to expose a flaw in the regex, but it doesn't; it's the input that's invalid. The goal was to match quoted strings, optionally containing backslash-escaped quotes, embedded in other text--why would there be escaped quotes outside of quoted strings? If you really need to support that, you have a much more complex problem, requiring a very different approach.

As I said, the above is how the regex should look to the regex compiler. But you're writing it in the form of a string literal, and those tend to treat certain characters specially--i.e., backslashes and quotation marks. Fortunately, C#'s verbatim strings save you the hassle of having to double-escape backslashes; you just have to escape each quotation mark with another quotation mark:

Regex r = new Regex(@"""[^""\\]*(?:\\.[^""\\]*)*""");

So the rule is double quotation marks for the C# compiler and double backslashes for the regex compiler--nice and easy. This particular regex may look a little awkward, with the three quotation marks at either end, but consider the alternative:

Regex r = new Regex("\"[^\"\\\\]*(?:\\\\.[^\"\\\\]*)*\"");

In Java, you always have to write them that way. :-( By the way, if you want to make sure there are no line-separator characters in the quoted strings, you can include them in the negated character classes:

Regex r = new Regex(@"""[^""\r\n\\]*(?:\\.[^""\r\n\\]*)*""");

The dot in \\. already excludes line separators, as long as you don't specify the Singleline option.

Answer 8

Regex for capturing strings (with \ for character escaping), for the .NET engine:

(?>(?(STR)(?(ESC).(?<-ESC>)|\\(?<ESC>))|(?!))|(?(STR)"(?<-STR>)|"(?<STR>))|(?(STR).|(?!)))+   

Here, a "friendly" version:

(?>                            | especify nonbacktracking
   (?(STR)                     | if (STRING MODE) then
         (?(ESC)               |     if (ESCAPE MODE) then
               .(?<-ESC>)      |          match any char and exits escape mode (pop ESC)
               |               |     else
               \\(?<ESC>)      |          match '\' and enters escape mode (push ESC)
         )                     |     endif
         |                     | else
         (?!)                  |     do nothing (NOP)
   )                           | endif
   |                           | -- OR
   (?(STR)                     | if (STRING MODE) then
         "(?<-STR>)            |     match '"' and exits string mode (pop STR)
         |                     | else
         "(?<STR>)             |     match '"' and enters string mode (push STR)
   )                           | endif
   |                           | -- OR
   (?(STR)                     | if (STRING MODE) then
         .                     |     matches any character
         |                     | else
         (?!)                  |     do nothing (NOP)  
   )                           | endif
)+                             | REPEATS FOR EVERY CHARACTER

Based on http://tomkaminski.com/conditional-constructs-net-regular-expressions examples. It relies in quotes balancing. I use it with great success. Use it with Singleline flag.

To play around with regexes, I recommend Rad Software Regular Expression Designer, which has a nice "Language Elements" tab with quick access to some basic instructions. It's based at .NET's regex engine.