XSLT: not contains check

Question

I need to create XSL that checks a "does not contain" condition. For example, my XML is like this:

<Categories>
  <category>
    <blog>ABC</blog>
    <link>http://www.msdn.com&lt;/link&gt;
  </category>
</Categories>

I want to show every <blog> where <link> does not contain "msdn". I don't want to use equals because I just want to check part of the link.

Answer 1

Use the not function with the contains function.

Example: not(contains('XML','XM'))

Result: false

http://www.w3schools.com/Xpath/xpath_functions.asp

Answer 2

I'm not sure exactly what HTML output you want, but hopefully this can get you started.

<xsl:template match="category">
    <xsl:if test="not(contains(link, 'msdn'))">
        <a href="{link}">
            <xsl:value-of select="blog" />
        </a>
    </xsl:if>
</xsl:template>

You could also include the test in the template match (or the apply-templates select) predicate like this:

<xsl:template match="category[not(contains(link, 'msdn'))]">

Answer 3

Xpath for xsl:apply-templates or xsl:value-of should contain following

/Categories/category/blog[not( contains(following-sibling::link/text(), 'msdn'))]