How to correctly define char array

Question

Hi all,

Does anyone know how should ASF_OBJECT_GUID_TEST be defined to avoid compilation error in the line marked below, or where I can find more information about it?

Thanks,

Andre

#define ASF_OBJECT_GUID_TEST {(char)0x75, (char)0xB2, (char)0x00}

void testFunction(char * testChar)
{

}

int main(int argc, char * argv[])
{
   char test[] = ASF_OBJECT_GUID_TEST;

   testFunction(test);
   testFunction(ASF_OBJECT_GUID_TEST); // <- fails to compile this line of code

   return 0;
}

Answer 1

{(char)0x75, (char)0xB2, (char)0x00}

is an initializer list and is not itself an array (or a pointer) in C89.

You instead could use:

#define ASF_OBJECT_GUID_TEST "\x75\xB2"

Answer 2

you want to cast the ASF_OBJECT_GUID_TEST, i.e

testFunction((char[])ASF_OBJECT_GUID_TEST)

or

#define ASF_OBJECT_GUID_TEST (char[]){(char)...}

Answer 3

Thanks. That was exactly what I was looking for.

Supposed I have defined many string literals which have 8 characters, and each 2 of them make actually the value of a byte. Is there a way to create a macro that would modify those string literals by adding a "\x" between every couple of characters like the following?

#define TEST SOME_MACRO("33698149")

Where TEST would be "\x33\x69\x81\x49"