views:

288

answers:

4

I have a class Cell:

public class Cell
{
    public enum cellState
    {
        WATER,
        SCAN,
        SHIPUNIT,
        SHOT,
        HIT
    }

    public Cell()
    {
        currentCell = cellState.WATER;
        MessageBox.Show(currentCell.ToString());
    }

    public cellState currentCell { get; set; }
}

I then try to use it in the following class:

public class NietzscheBattleshipsGameModel
{
    private byte MAXCOL = 10;
    private byte MAXROW = 10;

    public Cell[,] HomeArray;

    private Cell[,] AwayArray;

    public NietzscheBattleshipsGameModel()
    {
        HomeArray = new Cell [MAXCOL, MAXROW];

        AwayArray = new Cell [MAXCOL, MAXROW];
    }


    public string alphaCoords(Int32 x)
    {
        if (x < 0 || x > 9)
        {
            throw new ArgumentOutOfRangeException();
        }

        char alphaChar = (char)('A' + x);

        return alphaChar.ToString();
    }

    public void test()
    {
        for (int i = 0; i < 10; i++)
        {
            for (int j = 0; j < 10; j++)
            {

                // Object reference not set to an instance of an object.
                MessageBox.Show(HomeArray[i,j].currentCell.ToString());
                ///////////////////////////////////////////////////////

            }
        }
    }
}

I end up with the Object reference not set to an instance of an object (between the ///// in the above code..

I have tried creating a single instance of Cell and it works fine.

+1  A: 

Arrays are initialised to be empty - the Null reference is because HomeArray[i,j] is null, not because HomeArray[i,j].currentCell is null.

UPDATE: If you have a statement where a couple of different things could be null, then I generally split that up into multiple lines to make it easier to tell what is null.

For example, in your case:

MessageBox.Show(HomeArray[i,j].currentCell.ToString());

Either HomeArray[i,j] or HomeArray[i,j].currentCell could potentially be null and trigger a NullReferenceException - there is no way to tell which it was from the exception. If you split that statement up however:

Cell cell = HomeArray[i,j].currentCell;
MessageBox.Show(cell.ToString());

In this case if HomeArray[i,j] is null then you get your NullReferenceException on the first, line whereas if cell is null you get it on the second line.

Kragen
i got the part: arrays are initialised to be empty. then i do not understand the rest of it sorry. please be kind enough to inform me further.
iEisenhower
@ikurtz - I've tweaked my answer a little bit, is it any clearer?
Kragen
A: 

You are getting the exception because you are not assigning an instance of Cell to any of the slots of your matrices.

Otávio Décio
+9  A: 

When you instantiate an array, the items in the array receive the default value for that type. Thus for

T[] array = new T[length];

it is the case that for every i with 0 <= i < length we have array[i] = default(T). Thus, for reference types array[i] will be null. This is why you are seeing the NullReferenceException. In your case Cell is a reference type so since you have

HomeArray = new Cell [MAXCOL, MAXROW]; 

and all you have done is establish an array of references to Cells but you never assigned those references to instances of Cell. That is, you told the compiler "give me an array that can hold references to Cells" but you did not tell the compiler "give me an array that can hold references to Cells and assign each of those references to a new instance of Cell." Thus, the compiler will set the initial value of those references to null. Therefore you need to initialize the HomeArray:

for (int i = 0; i < MAXCOL; i++)  { 
    for (int j = 0; j < MAXROW; j++)  { 
        HomeArray[i, j] = new Cell();
    } 
}
Jason
+2  A: 

You need to initialize the Cells in your arrays.

public NietzscheBattleshipsGameModel()
{
    HomeArray = new Cell[MAXCOL, MAXROW];
    AwayArray = new Cell[MAXCOL, MAXROW];

    for (int i = 0; i < MAXROW; i++)
    {
        for (int j = 0; j < MAXCOL; j++)
        {
            HomeArray[i,j] = new Cell();
            AwayArray[i,j] = new Cell();
        }
    }
}
Austin Salonen
ah ok i got it now. i thought the declaration of it would be enough. thanks to all for your good advise.
iEisenhower