Python: Retrieving only POP3 message text, no headers

Question

I'm trying to make a Python program that retrieves only the body text of an email without passing headers or any other parameters. I'm not sure how to go about this.

The goal is to be able to send basic commands to a program via message text.

What I have now is this:

import poplib

host = "pop.gmail.com"
mail = poplib.POP3_SSL(host)
print mail.getwelcome()
print mail.user("user")
print mail.pass_("pass")
print mail.stat()
print mail.list()
print ""

if mail.stat()[1] > 0:
    print "You have new mail."
else:
    print "No new mail."

print ""

numMessages = len(mail.list()[1])
for i in range(numMessages):
    for j in mail.retr(i+1)[1]:
        print j

mail.quit()
input("Press any key to continue.")

Which is all fine, except when "print J" is executed it prints the entire message, including headers. I just want to extract the body text without any additional garbage.

Can anyone help? Thanks!

Answer 1

You can parse eMails using the email module.

Answer 2

This is a fragment of code from my own POP3 reader:

        response, lines, bytes = pop.retr(m)

        # remove trailing blank lines from message
        while lines[-1]=="": 
            del lines[-1]

        try:
            endOfHeader = lines.index('')
            header = lines[:endOfHeader]
            body = lines[endOfHeader+1:]
        except ValueError:
            header = lines
            body = []

This keys off the first empty line in the list of all lines as the end of the header info. Then just list slice from there to the end for the message body.