echo prints out -e inside script

Question

when I run it in the terminal (bash)

echo -e ."\c"

prints out . and suppresses the newline.

When I run the following script (all the code)

echo -e ."\c"
echo -e ."\c"

it prints out .. and suppresses the newlines.

when I run it inside a script with the shebang (!#/bin/sh), it prints out -e . -e . and suppresses the newline.

Why? and how can I prevent this?

EDIT: I want to prevent the -e's from printing out, so my output should be . .

Answer 1

you need to give the absolute path to echo if your shebang line is invoking sh. Or just changes the shebang to use bash.

Answer 2

change your script shebang to #!/bin/bash instead of #!/bin/sh and see if it works