Program needing elevation in Startup registry key (windows 7)

Question

Hi all,

I have a program that I'd to run when the computer starts. I've put its path inside "SOFTWARE\Microsoft\Windows\CurrentVersion\Run". This is in Windows 7. When the computer starts nothing happens. I'm thinking this is because the program needs elevation when I run it. But Windows does not ask for permission to elevate and gives no feedback. It simply ignores it. I've read that Vista tells you that the program was blocked etc. Does anybody have any idea why Windows 7 simply ignores the application?

Thank you very much in advance.

Alireza

Answer 1

Just a thought... but I had a similar problem because the path to my executable had slashes (/) instead of backslashes ().

I know it's dumb, but I had that issue.