views:

281

answers:

4

Suppose I have a datetime field whose value is 2000-01-01 08:30:00

and a duration field whose value is say 00:15( meaning 15 minutes)

If I subtract these two, I should get 2000-01-01 08:15:00

I am trying like SELECT DATEDIFF(minute, '00:15','2000-01-01 08:30:00');

But the output is 52595055. How can i get the desired result.

N.B.~ If I do like SELECT dateadd(minute, -15,'2000-01-01 08:30:00'); , I will get the desired result but that involves parsing the minute field.

Also if I want to subtract 1:15( means 1 hour 15 minutes), the output will be 2000-01-01 07:15:00

Edit:

As per the answers I got here every one is suggesting to convert everything into minutes and then to subtract like if it is 1:30 means i need to subtract 90 minutes. That's fine. Any other way without converting to minutes?

Thanks

A: 

You want to use DATEADD, using a negative duration. e.g.

DATEADD(minute, -15, '2000-01-01 08:30:00') 
Mitch Wheat
So you mean to say that to convert everything into minutes and then to subtract like if it is 1:30 means i need to subtract 90 minutes. That's fine. Any other way without converting to minutes?
priyanka.bangalore
+2  A: 
SELECT DATEADD(minute, -15, '2000-01-01 08:30:00'); 

The second value (-15 in this case) must be numeric (i.e. not a string like '00:15'). If you need to subtract hours and minutes I would recommend splitting the string on the : to get the hours and minutes and subtracting using something like

SELECT DATEADD(minute, -60 * @h - @m, '2000-01-01 08:30:00'); 

where @h is the hour part of your string and @m is the minute part of your string

EDIT:

Here is a better way:

SELECT CAST('2000-01-01 08:30:00' as datetime) - CAST('00:15' AS datetime)
Martin Booth
I am sorry but I was editing while you posted the answer. I donot want to parse that.
priyanka.bangalore
So you mean to say that to convert everything into minutes and then to subtract like if it is 1:30 means i need to subtract 90 minutes. That's fine. Any other way without converting to minutes?
priyanka.bangalore
Sorry I edited my answer after I realised I hadn't provided a very good solution; multiplying by 1440 (the number of minutes in a day) converts days to minutes. Previously I was casting a datetime to a float to get a number representing days hence the conversion.. I have since changed my answer so that it does not require conversion to minutes at all
Martin Booth
+1  A: 

Use DATEPART to pull apart your interval, and DATEADD to subtract the parts:

select dateadd(
     hh,
    -1 * datepart(hh, cast('1:15' as datetime)),
    dateadd(
        mi,
        -1 * datepart(mi, cast('1:15' as datetime)),
        '2000-01-01 08:30:00'))

or, we can convert to minutes first (though OP would prefer not to):

declare @mins int
select @mins = datepart(mi, cast('1:15' as datetime)) + 60 * datepart(hh, cast('1:15' as datetime)) 
select dateadd(mi, -1 * @mins, '2000-01-01 08:30:00')
Lachlan Roche
So you mean to say that to convert everything into minutes and then to subtract like if it is 1:30 means i need to subtract 90 minutes. That's fine. Any other way without converting to minutes?
priyanka.bangalore
A: 

Have you tried

SELECT DATEADD(mi, -15,'2000-01-01 08:30:00')

DATEDIFF is the difference between 2 dates.

astander
So you mean to say that to convert everything into minutes and then to subtract like if it is 1:30 means i need to subtract 90 minutes. That's fine. Any other way without converting to minutes?
priyanka.bangalore