You need to implement the equals()
and hashCode()
methods to implement object equality in Java:
class Rec {
private BigDecimal recordId = null;
private BigDecimal recSubNum = null;
private BigDecimal FileId = null;
private String category = null;
private BigDecimal status = null;
private BigDecimal errorCode = null;
@Override
public int hashCode() {
int ret = 41;
ret = hc(ret, recordId);
ret = hc(ret, recSubNum);
ret = hc(ret, fieldId);
ret = hc(ret, category);
ret = hc(ret, status);
ret = hc(ret, errorCode);
return ret;
}
@Override
public boolean equals(Object ob) {
if (ob == null) return false;
if (ob.getClass() != Rec.class) return false;
Rec r = (Rec)ob;
if (!eq(r.recordId, record)) return false;
if (!eq(r.recSubNum, recSubNum)) return false;
if (!eq(r.fileId, fileId)) return false;
if (!eq(r.category, category)) return false;
if (!eq(r.status, status)) return false;
if (!eq(r.errorCode, errorCode)) return false;
return true;
}
private static boolean eq(Object ob1, Object ob2) {
return ob1 == null ? ob2 == null : ob1.equals(ob2);
}
private static int hc(int hc, Object field) {
return field == null ? hc : 43 + hc * field.hashCode();
}
}
Note: the equals/hashCode contract for Java means that for any two objects a and b:
a.equals(b) == b.equals(a)
and if two objects are equal then a.hashCode()
must equal b.hashCode()
.
Edit: there are two ways of checking if the types match. Either:
if (ob == null) return false;
if (ob.getClass() != Rec.class) return false;
or
if (!(ob instanceof Rec)) return false;
These two do different things and you should select the correct one depending on what you want to do. I generally prefer the first one unless you know you need the second. What's the difference?
class A {
public int i;
public boolean equals(Object ob) {
if (!(ob instanceof A)) return false;
return i == ((A)ob).i;
}
}
Looks reasonable right? What if the class gets extended:
class B extends A {
public int j;
public boolean equals(Object ob) {
if (!(ob instanceof B)) return false;
if (!super.equals(ob)) return false;
return j == ((B)ob).j;
}
}
Still looks reasonable? It's broken.
A a = new A();
a.i = 10;
B b = new B();
b.i = 10;
b.j = 20;
System.out.println(a.equals(b)); // true! Is this really what you want?
System.out.println(b.equals(a)); // false! Different to previous = problem.
That's why I favour getClass()
over instanceof
unless I really want subclass equality.