I am trying to identify table types based on the columns they contain in a stored procedure. The query I initialy came up with is as follows:
SELECT CASE WHEN col_one. IS NOT NULL THEN 'COL1'
WHEN col_two IS NOT NULL THEN 'COL2'
ELSE 'NEITHER'
END
INTO ls_table_type
FROM (SELECT column_name col_one
FROM sys.all_tab_cols
WHERE upper ( owner ) = upper ( '|OWNER|' )
AND hidden_column = 'NO'
AND virtual_column = 'NO'
AND column_id IS NOT NULL
AND column_name = '|COL1_NAME|'
AND table_name = upper(|TABLE_NAME|))
,(SELECT column_name as col_two
FROM sys.all_tab_cols
WHERE upper ( owner ) = upper ( '|OWNER|' )
AND hidden_column = 'NO'
AND virtual_column = 'NO'
AND column_id IS NOT NULL
AND column_name = '|COL2_NAME|'
AND table_name = upper(|TABLE_NAME|))
This does not work unless both columns are present in a table. I am sure I am missing some obvious way of attacking this.