jQuery selector for inputs with square brackets in the name attribute

Question

I want to do this:

$('input[inputName=someValue]')

Except that the name of the input is not 'inputName', it is 'inputName[]'. And this doesn't work:

$('input[inputName[]=someValue]')

and neither does this:

$('input[inputName[]=someValue]')

or this

$('input["inputName[]"=someValue]')

Thanks for any help.

EDIT:

As some of you have pointed out, $('input[inputName=someValue]') would never work. What i was trying to do was $('input[name=inputName][value=someValue]'). (But with [] in the name attribute).

Thanks for all your help.

Answer 1

The attribute selector syntax is [name=value] where name is the attribute name and value is the attribute value.

So if you want to select all input elements with the attribute name having the value inputName[]:

$('input[name="inputName[]"]')

And if you want to check for two attributes (here: name and value):

$('input[name="inputName[]"][value=someValue]')

Answer 2

You can use backslash to quote "funny" characters in your jQuery selectors:

$('#input\\[23\\]')

For attribute values, you can use quotes:

$('input[name="weirdName[23]"]')

Now, I'm a little confused by your example; what exactly does your HTML look like? Where does the string "inputName" show up, in particular?

edit fixed bogosity; thanks @Dancrumb

Answer 3

Try this:

$('input[name="inputName\\[\\]"]')

You need to escape the brackets [ ] using backslash.

Answer 4

Per the jQuery documentation, try this:

$('input[inputName\\[\\]=someValue]')

[EDIT] However, I'm not sure that's the right syntax for your selector. You probably want:

$('input[name=inputName\\[\\]][value=someValue]')