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Creating WebControls from fully qualified path (assembly name?)

Answer 1

+1 A:

object widget = Activator.CreateInstance ( Assembly.GetType ( name ) );

where name is the string of the fully qualified type

JDMX 2010-03-02 18:18:34

The only thing to remember is that the `Activator` only works with public classes that implements a default constructor, that is, a parameterless constructor.

Paulo Santos 2010-03-02 18:30:42

I think this is close, but not quite there yet. Assembly has no static method of GetType(), but an instance of Assembly does, of course.

Jagd 2010-03-02 18:57:37

you can also do typeof( x ) to get the type needed for Activator.CreateInstance. x then equals System.Web.UI.WebControls.Label, System.Web.UI.WebControls.Textbox, or any other type you want to dynamically create

JDMX 2010-03-02 19:01:28

Answer 2

+2 A:

try to call this way: Activator.CreateInstance(Type.GetType("TypeName"));

where TypeName is fully qualified name, including assembly. in my case it looked this way:

Activator.CreateInstance(Type.GetType("System.Web.UI.WebControls.Label, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a"));

to be sure about full name in your case, try to output typeof(System.Web.UI.WebControls.Label).FullName and use it as a pattern

Andrey 2010-03-02 18:21:26

The only thing to remember is that the `Activator` only works with public classes that implements a default constructor, that is, a parameterless constructor.

Paulo Santos 2010-03-02 18:31:14

i disagree. It can instantiate private classes if you manage to dig out Type object from Assembly object. about parameterless contructor also not true, you can pass parameters to constructor as second parameter to CreateInstance

Andrey 2010-03-02 18:37:51

This works. Thank you!

Jagd 2010-03-02 19:05:39

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Creating WebControls from fully qualified path (assembly name?)

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