$('#menu .sub-right').css( 'paddingLeft', $('#menu .sub-left').width() );
nor
$('#menu .sub-right').css({'padding-left': $('#menu .sub-left').width()});
...these work. What am I doing wrong?
Thanks!
$('#menu .sub-right').css( 'paddingLeft', $('#menu .sub-left').width() );
nor
$('#menu .sub-right').css({'padding-left': $('#menu .sub-left').width()});
...these work. What am I doing wrong?
Thanks!
Does this work?
$('#menu .sub-right').css( 'padding-left', $('#menu .sub-left').width()+"px" );
The width function documentation states:
The difference between .css(width) and .width() is that the latter returns a unit-less pixel value (for example, 400) while the former returns a value with units intact (for example, 400px). The .width() method is recommended when an element's width needs to be used in a mathematical calculation.
But since CSS expects ###px, you can use the above code or this code:
$('#menu .sub-right').css( 'padding-left', $('#menu .sub-left').css('width') );
Either one should work.