Here's a link: Chapter 6. Collection mapping
Here's another useful link: Chapter 7. Association Mappings
EDIT
After having reasearched for an entire evening, I came to the following conclusion:
- Considering NHibernate Best Practices, what you wish to do is no good;
Don't use exotic association mappings.
Good usecases for a real many-to-many associations are rare. Most of the time you need additional information stored in the "link table". In this case, it is much better to use two one-to-many associations to an intermediate link class. In fact, we think that most associations are one-to-many and many-to-one, you should be careful when using any other association style and ask yourself if it is really neccessary.
- As a programming philosophy, I prefer to keep it simple than having to write clever code where even me would no more understand what I wrote after a certain time;
- Plus, I even considered using the subquery element of association mapping which would have worked if I would have found a way to parameterize it, if it is doable, but it seems it won't let me parameterize the query with the User instance's Id property value;
- In the optic of a well designed OO model, a child being aware of his parent's properties is fine, but a parent accessing a child's property makes no sens - design smell;
As I may understand considering the context exposed the benefits of having permissions or MenuItemKey values accessible from the User directly, I suggest the following solution:
- Create yourself a user defined dataview which will hold the values related to the MenuItemKey Permission attribute gotten through the Roles the User is a member like so:
CREATE VIEW udvUsersPermissions AS
SELECT UR.UserID, P.ID as N'ID', P.MenuItemKey
FROM Users U
INNER JOIN UsersRoles UR ON UR.UserID = U.ID
INNER JOIN Roles R ON R.ID = UR.RoleID
INNER JOIN Permissions P ON P.RoleID = R.ID
GO
Then, map it according in you User.hbm.xml file:
<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2">
<class name="User" table="Users">
<id name="Id" column="ID">
<generator class="identity"/>
</id>
<property name="Name" length="100"/>
<property name="UserName" length="10" not-null="true"/>
<property name="Password" length="10" not-null="true"/>
<property name="IsActive" not-null="true"/>
<list name="Roles" table="UsersRoles" access="private-property" lazy="true">
<key column="UserID" foreign-key="FK_UR_U"/>
<list-index column="UserID"/>
<many-to-many class="Role" column="RoleID" />
</list>
<!-- Here mapping Permissions granted to User. -->
<list name="Permissions" table="udvUsersPermissions" lazy="true">
<key column="UserID"/>
<list-index column="MenuItemKey"/>
<many-to-many column="ID" class="Permission"/>
</list>
</class>
</hibernate-mapping>
And here, I will let you know about the subselect solution, in case it works the way I didn't expect it to.
<list name="Permissions" lazy="true">
<subselect> <!-- see section 7.6, Chapter 7 - Association mappings -->
select U.ID, P.ID, P.MenuItemKey
from Users U
inner join UsersRoles UR ON UR.UserID = U.ID
inner join Roles R ON R.ID = UR.RoleID
inner join Permissions P ON P.RoleID = R.ID
group by U.ID, P.ID, P.MenuItemKey
order by P.MenuItemKey
</subselect>
<key column="U.ID"/>
<list-index column="P.MenuItemKey"/>
<many-to-many class="Permission" column="P.ID"/>
</list>
Now, I hope I brought enough details so that it helps you achieve what you want to do or either get on track. =)