JQuery Select Input Fields Except Hidden

Question

I have a row in a table which contains a checkbox and some other form fields (text boxes, hidden fields, select lists). When the checkbox is checked I want to disable all form fields in that row except for the hidden fields. I have this working for the most part, but I can't seem to ignore the hidden fields.

What is the best way to select all form fields in a table row but ignore hidden fields in the selection?

Answer 1

.........

$('tr input').attr('disabled', true)
$('tr input[type="hidden"]').removeAttr('disabled')

Answer 2

Assuming by "hidden" you mean type="hidden" ie:

<input type="hidden" name="foo" value="bar">

then you can use the attribute not equals selector to do this:

$("tr input:checkbox").click(function() {
  var cb = $(this);
  var tr = $(this).closest("tr");
  if (cb.val()) {
    tr.find("input[type!='hidden']").attr("disabled", true);
  } else {
    tr.find("input[type!='hidden']").removeAttr("disabled");
  }
});

My general advice is avoid attribute selectors. They're slow. Give the relevant inputs (either the hidden ones or the not hidden ones) a class and then use that in the selectors.

If however you mean "hidden" as in "not visible" then use the :visible selector:

$("tr input:checkbox").click(function() {
  var cb = $(this);
  var tr = $(this).closest("tr");
  if (cb.val()) {
    tr.find("input:visible").attr("disabled", true);
  } else {
    tr.find("input:visible").removeAttr("disabled");
  }
});

Answer 3

First, you need to tag your "selector" checkbox (e.g. with a class attribute "selector) so that it is clear that it is used for checking instead of regular form element. Then you use this:

$('table :checkbox.selector').click(function(ev) {
    $(ev.currentTarget)
            .parents('td').siblings('td')
            .find(':input:not([type=hidden])')
            .attr('disabled', ev.currentTarget.checked);
});

This solution works for all inputs (eg. select lists, textareas) and it doesn't disable the selector checkbox itself.

I'm assuming you use latest jQuery.