Unexpected result from printf

Question

#include<stdio.h>
int main()
{
    printf("He %c llo",65);
}

Output: He A llo

#include<stdio.h>
int main()
{
    printf("He %c llo",13);
}

Output: llo. It doesnt print He.

I can understand that 65 is ascii value for A and hence A is printed in first case but why llo in second case.

Thanks

Answer 1

Man ascii:

Oct   Dec   Hex   Char
015   13    0D    CR  '\r'

Character 13 is carriage return so it prints He then returns to the beginning of the line and prints the remining llo.

Answer 2

ASCII 13 is carriage return, which on some systems simply moves the cursor to the beginning of the line you were just on.

Further characters then wipe out the earlier text.