This one is quite obviously a function pointer :
typedef int (* foobar) (int a, unsigned char *b, unsigned int c);
But what does this one do?
typedef int (foobar *) (int a, unsigned char *b, unsigned int c);
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A:
It produces a compiler error, at least in GCC 4.3:
foo.cpp:1: error: expected `)' before '*' token
Brooks Moses
2010-03-12 06:11:46
The code hasn't been run yet, but it was written by an experienced coder. It's for CodeWarrior BTW.
Quicksilver
2010-03-12 06:14:59
Even experienced coders make typos. :)
vladr
2010-03-12 06:16:45
Just confirmed that it was a mistake. Thanks y'all! :)
Quicksilver
2010-03-12 06:41:43