Use a grepped file as an included source in bash

Question

I'm on a shared webhost where I don't have permission to edit the global bash configuration file at /ect/bashrc. Unfortunately there is one line in the global file, mesg y, which puts the terminal in tty mode and makes scp and similar commands unavailable. My local ~./bashrc includes the global file as a source, like so:

# Source global definitions
if [ -f /etc/bashrc ]; then
    . /etc/bashrc
fi

My current workaround uses grep to output the global file, sans offending line, into a local file and use that as a source.

# Source global definitions
if [ -f /etc/bashrc ]; then
    grep -v mesg /etc/bashrc > ~/.bash_global
    . ~/.bash_global
fi

Is there a way to do include a grepped file like this without the intermediate step of creating an actual file? Something like this?

. grep -v mesg /etc/bashrc > ~/.bash_global

Answer 1

I suggest to call mesg n :)

Answer 2

From memory, but something like

grep -v mesg /etc/bashrc | eval

should do the trick

Since i'm not sure eval will read stdin, you may need to rephrase it into

eval `grep -v mesg /etc/bashrc`

Answer 3

. <(grep -v mesg /etc/bashrc)

Answer 4

lose the cat, its useless

source <(grep -v "mesg" /etc/bashrc)

the <() syntax is called process substitution.