How to get tag parameter value with XQuery

Question

For example i have this xml. I need to get value of parameter val of tag foo with id="two"

<top>
    <sub id="one">
        <foo id="two" val="bar" />
        sometext
    </sub>
</top>

Whis this query (using Qt QXmlQuery):

doc('test.xml')/top/sub[@id='one']/foo[@id='two']/<p>{@val}</p>

I receive <p val="bar"/>, but I need only text "bar" without any tags. I tried to remove <p> and </p> and receive syntax error, unexpected {

How can i get parameter value without any tags?

Answer 1

doc('test.xml')/top/sub[@id='one']/foo[@id='two']/@val

Answer 2

If you try to serialize just an attribute you will get an error. You may be better off just retrieving the value of the attribute:

doc('test.xml')/top/sub[@id='one']/foo[@id='two']/@val/data(.)

Answer 3

Hi Sorry a bit late in the day... try

data(doc('/db/test/test.xml')/top/sub[@id='one']/foo[@id='two']/@val)

which returns just the text value of the attribute